chrome会报这个错误:
Refused to get unsafe header
解决方案:

服务器脚本,比如php控制器init函数里面加入

header('Access-Control-Allow-Origin:http://xxx.com'); 
header('Access-Control-Allow-Methods:POST');  // 响应类型  
header('Access-Control-Allow-Headers:x-requested-with,content-type,authcode');  // 响应头设置
header('Access-Control-Expose-Headers: xxx自定义头字段');//important

前端代码

<!DOCTYPE html>
<html>
<head>
<script src="jquery-3.3.1.min.js">
</script>
<script>
$(document).ready(function(){
  $("button").click(function(){
    /*    $.ajax({
    type: "POST",
    url: "http://api.com/auth/sign-in",
    data:{"email":"xxx@qq.com","password":"123456"},
    dataType: "json",
    success: function(data,textStatus, request) {
        //console.log(data);
        console.log(textStatus);
        var obj = request.getResponseHeader("xxx自定义字段");//["content-type"]
        console.log(obj);
    }
        });*/

    var xhr = new XMLHttpRequest();
    xhr.withCredentials = true; //solution : Refused to get unsafe header in chrome,server setting : header('Access-Control-Expose-Headers: authcode');
                xhr.open('post', 'http://test.com/auth/sign-in',true);
                xhr.setRequestHeader("Content-type","application/x-www-form-urlencoded");
                xhr.onload = function () {
                    console.log('load:', xhr.getAllResponseHeaders());
                    console.log(xhr.getResponseHeader('xxx自定义字段'));
                  console.log('=================================')};
                var data = "email=xxx@qq.com&password=123456";
                xhr.send(data);
});
})
</script>
</head>
<body>
<button>test</button>
</body>
</html>